Photos of Interactive Mathematics Miscellany and Puzzles

    
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I found a theorem following: Let hexagon ABCDEF. AC meets BD at G, BE meets CF at H, AE meets DF at I. Then G,H,I are collinear <=> A,B,C,D,E,F lie on a conic <=> GB/GD*ID/IF*HF/HC*GC/GA*IA/IF*HF/HB=1

I named it is Viet Nam hexagon theorem (a generalization power of a point with conic)